2 cap I equals integral from 0 to pi / 2 of l n open paren sine x cosine x close paren space d x 3. Utilize Double Angle Identity
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1 over 16 end-fraction arc tangent open paren x over 2 end-fraction close paren plus the fraction with numerator x and denominator 8 open paren x squared plus 4 close paren end-fraction plus cap C The solution is 2 cap I equals integral from 0 to
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